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[单选题]牛顿法的初始雅可比矩阵python代码为

Ajacobi_m = np.matrix([grad_1_value,grad_2_value])Jut答案窝(daanwo.com)-大学生作业答案及考资分享平台

Bjacobi_m = np.matrix([grad_11_value,grad_12_value])Jut答案窝(daanwo.com)-大学生作业答案及考资分享平台

Cjacobi_m = np.matrix([[grad_11_value,grad_12_value],[grad_21_value,grad_22_value]])Jut答案窝(daanwo.com)-大学生作业答案及考资分享平台

Djacobi_m = np.matrix([[grad_11_value,grad_12_value],[grad_21_value,grad_22_value]])Jut答案窝(daanwo.com)-大学生作业答案及考资分享平台

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