问题:
[单选题]
Aτ=[3(m2h2−m1h1)/(m1−m2)g]1/2
Bτ=[2(m2h2−m1h1)/(m1−m2)g]5/2
Cτ=[2(m2h2−m1h1)/(m1−m2)g]3/2
Dτ=[2(m2h2−m1h1)/(m1−m2)g]1/2
Aτ=[3(m2h2−m1h1)/(m1−m2)g]1/2
Bτ=[2(m2h2−m1h1)/(m1−m2)g]5/2
Cτ=[2(m2h2−m1h1)/(m1−m2)g]3/2
Dτ=[2(m2h2−m1h1)/(m1−m2)g]1/2
Copyright © 2024 www.daanwo.com All Rights Reserved |